Question

The compressed gas in a sealed container has a gauge pressure of 185.4 kilopascals. If the air around the container is at standard pressure, what is the absolute pressure inside the container?

A.
84.1 kPa
B.
143.4 kPa
C.
184.4 kPa
D.
186.4 kPa
E.
286.7 kPa

Answer 1

The gauge pressure ($P_G$) is defined as the difference between the absolute pressure($P_T$) and the atmospheric pressure ($P_A$).

Therefore the formula is,

$P_G= P_T-P_A$.

Solve for $P_T$, and use 101.32kPA as atmospheric pressure, since the air around the container is at standard pressure.

$P_T= P_G + P_A\\P_T=185.4kPA + 101.32kPA\\P_T=286.72kPA$

The correct answer is E.

Answer 2

Hii friend,

◆ Answer-
286.7 kPa

◆ Explaination-
# Given-
Gauge pressure = 185.4 kPa
Atmospheric pressure = 101.3 kPa

# Solution-
Guage presure is given by -

Guage pressure = Pressure inside container - Atmospheric pressure

Pressure inside container = Guage pressure + Atmospheric pressure

Pressure inside container = 185.4 + 101.3 = 286.7 kPa

Absolute pressure inside container is 286.7 kPa.

Hope this helps...