The concentration of a 100 ml solution containing x grams of na2co3 is ym .the values of x and y are
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27
x is the actual mass of Na2CO3 contained in the solution (100ml)
y refers to the molarity of the solution
y is the number of moles of Na2CO3 that can be contained in 1000ml (1 litre) of the solution.
To get y, we divide x by molar mass of Na2CO3 then multiply by volume in litres.
Volume in litres = 100/1000 = 10 L
Molar mass of Na2CO3 = 106 g/mol
so;
y = [x/106]/10 = x/1060
y refers to the molarity of the solution
y is the number of moles of Na2CO3 that can be contained in 1000ml (1 litre) of the solution.
To get y, we divide x by molar mass of Na2CO3 then multiply by volume in litres.
Volume in litres = 100/1000 = 10 L
Molar mass of Na2CO3 = 106 g/mol
so;
y = [x/106]/10 = x/1060
Answered by
8
Answer:
Explanation:
x is the actual mass of Na2CO3 contained in the solution (100ml)
y refers to the molarity of the solution
y is the number of moles of Na2CO3 that can be contained in 1000ml (1 litre) of the solution.
To get y, we divide x by molar mass of Na2CO3 then multiply by volume in litres.
Volume in litres = 100/1000 = 10 L
Molar mass of Na2CO3 = 106 g/mol
so;
y = [x/106]/10 = x/1060
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