Question

The conductivity of pure water is 5.5x10^-8.the resistance measured for this sample of conductivity cell is

Answer 1

∵ conductivity = 1/resistivity
Given, conductivity = 5.5 × 10⁻⁸ Ω⁻¹m⁻¹
So, resistivity = 1/5.5 × 10⁻⁸ Ω = 1.88 × 10⁷ Ωm

Also we know,
Resistance = resistivity × cell Constant
Cell Constant is not given .
Let cell Constant is K
Then, resistance = 1.88 × 10⁷K Ω