Chemistry, asked by sontiger8810, 1 year ago

The conductivity of water at 298 k is 0.55*10^-7. if molar conductivity

Answers

Answered by ajay735
76
above question is solved
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Answered by skyfall63
28

The degree of dissociation of water is \bold{1.80 \times 10^{19}}

Explanation:

If the total substance dissociates into its ions are called degree of dissociation.

The dissociation of any molecule into positively charged and negatively charged ions.

Water molecule dissociated into hydronium and hydroxide ions.

The dissociation of water is as follows:

\begin{array}{c}{H_{2} O} \\ {c(1-\alpha)}\end{array} \leftrightarrow \begin{array}{l}{H^{+}} \\ {c \alpha}\end{array}+\begin{array}{c}{O H^{-}} \\ {c \alpha}\end{array}

\kappa=\left[H^{+}\right] \lambda_{m}\left(H^{+}\right)+\left[O H^{-}\right] \lambda_{m}\left(O H^{-}\right)=c \alpha\left[\lambda_{m}\left(H^{+}\right)+\lambda_{m}\left(O H^{-}\right)\right]

=\left[\frac{\left(\frac{\left(\frac{1000}{18}\right) m o l}{1 d m^{3}}\right]-\alpha\left[(350+200) S c m^{2} m o l^{-1}\right]}{1 d m^{3}}\right]

=\frac{0.55 \times 10^{-7} S \mathrm{cm}^{-1}}{\left(55.56 \mathrm{mol} \mathrm{dm}^{-3}\right)\left(550 \mathrm{S} \mathrm{cm}^{2} \mathrm{mol}^{-3}\right)}

\alpha=1.80 \times 10^{-9}

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