Math, asked by raun8700, 1 year ago

The difference of two natural number is 3 and their square have the sum 117

Answers

Answered by RöH84
0
X, Y
X-Y=3
X = 3+Y
X²+ Y² =117
(3+Y)² +Y² = 117
3²+Y²+6Y+Y² =117
9+ 2Y² + 6Y =117
then solve
Answered by Anonymous
30

Given:–

  • Sum of squares = 117
  • The two natural numbers differs by 3

To find:–

  • Two natural numbers

Concept:–

  • Simple equations (based on quadratic equation)

Step by step explaination:–

Let us assume the first number be y. Therefore, second number will be (y+3).

According to the question.

⟼ y² + (y+3)² = 117

Now, opening brackets and solving.

⟼ y² + y² + 6y + 9 = 117

⟼ 2y² + 6x - 108 = 117

⟼ y² + 3y - 54 = 0

⟼ (y+9) (y-9) = 0

Therefore,

⟼ y = -9 and 6

Answer:–

6 is accepted as -9 is not a natural number and being negative it can't be accepted.

Second number = 6+3 ⟼ 9

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