The cone height 8m has a curved surface area 188.4 square metre find its volume
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Given, height of the cone
h = 8
Let r is the radius and l is
the slant height of the
cone.
Given curved surface area
of the cone = 188.4
=> πrl = 188.4
=> πr√(r2 + h2 ) = 188.4 {since slant height l = √(r2 + h2 )}
=> 3.14*r√(r2 + 82 ) = 188.4
=> r√(r2 + 64 ) = 188.4/3.14
=> r√(r2 + 64 ) = 60
=> r2 *(r2 + 64 ) = (60)2
=> r4 + 64r2 = 3600
=> r4 + 64r2 - 3600 = 0
=> (r2 - 36)*(r2 + 100) = 0
=> r2 = 36, -100
Since square of a number can not be negative.
Hense, r2 = -100 is not possible
So, r2 = 36
=> r = ±6
Again since radius can not be negative.
So, r = 6
Now volume of the cone = (1/3)*πr2 h
= (1/3)*π*62h
= (3.41*36*8)/3
= 3.41*12*8
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