Question

the conpound interest on rs 6250 at 8% per annum for 1 year compounded half yearly​

Answer 1

$\huge\bold{Question:-}$

• The compound interest on rs 6250 at 8% per annum for 1 year compounded half yearly.

$\huge\bold{Given:-}$

• Principal = Rs. 6250

• Rate = 8%

• Time taken = 1yrs.

$\boxed {Note}$ :- Compound Interest is taken yearly.

$\huge\bold{To\:find:-}$

• Compound interest?

$\huge\bold{Formula\:used:-}$

• $a = p(1 + \dfrac{r}{100})t$

• $amount - principal = c.i.$

$\bold{Step-by-step-explanation:-}$

$= 6250(1 + \dfrac{8}{100})1$

$= 6250( \dfrac{100 + 8}{100})1$

$= 6250 \times \dfrac{108}{100} \times 1$

$= 6750$

Thus, Amount = Rs 6750

_________________

Compound interest = Amount - Principal

C.I. = 6750 - 6250

= Rs 500

Answer 2

Given :

• Compound Interest on Rs.6250 at 8% per annum for 1 year .

To Find :

• Compound Interest .

Solution :

$\longmapsto\tt{Principal(P)=Rs 6250}$

$\longmapsto\tt{Rate(r)=8\%}$

$\longmapsto\tt{Time(t)=1\:yr}$

Using Formula :

$\longmapsto\tt\boxed{Amount=P\bigg(1+\dfrac{r}{100}\bigg)^{t}}$

Putting Values :

$\longmapsto\tt{6250\bigg(1+\dfrac{8}{100}\bigg)^{1}}$

$\longmapsto\tt{6250\bigg(\dfrac{100+8}{100}\bigg)^{1}}$

$\longmapsto\tt{625{\not{0}}\bigg(\dfrac{108}{10{\not{0}}}\bigg)^{1}}$

$\longmapsto\tt{\dfrac{625\times{108}}{10}}$

$\longmapsto\tt{\dfrac{67500}{10}}$

$\longmapsto\tt\bf{Rs.6750}$

So , The Amount is Rs.6750 ..

Now ,

For Compound Interest :

$\longmapsto\tt{Amount-Principal}$

$\longmapsto\tt{6750-6250}$

$\longmapsto\tt\bf{Rs.500}$

So , The Compound Interest is Rs.500 ..