Question

the consecutive multiples of 5 whose sum is 105are_ and_​

Answer 1

Step-by-step explanation:

Consecutive multiplies os 5 are

Let be first number is equals to X

second number is equals to X + 5and third number is equals to X+5+5= X+10

x +x + 5 + X + 10 =105

3X+15=105

3X=105-15

3X=90

X=90/3

X=30

X+5=30+5=35

X+10=30+10=40

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Answer 2

$\huge\underline\bold\color{red}\mathfrak{Answer}$

Given:-

Two consecutive numbers which are multiples of 5 and whose sum = 105

To find:-

The numbers.

Solution :-

Let the first number be x, then the other two numbers are x+5

Their sum is 105.

Adding,

x + x + 5 = 105

2x + 5 = 105

2x = 105 - 5

2x = 100

x = 100/2

x = 50

The first number = x = 50

Second number = x+5 = 55

So the consecutive multiples of 5 whose sum is 105 are 50 and 55.

50 + 55 = 105

Hence verified.

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