the consecutive positive integer sum is equal to 63 what are the two number that we add
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Answered by
1
Let the numbers be x and x+1.
Then x+x+1 = 63
2x = 63-1
2x = 62
x = 63/2
x = 31
Now if x = 31 then x +1 = 32.
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Then x+x+1 = 63
2x = 63-1
2x = 62
x = 63/2
x = 31
Now if x = 31 then x +1 = 32.
Please mark as brainliest if it helps you...
Answered by
2
consecutive positive numbers are x and x+1 respectively.
given that sum of consecutive no is 63
So, x+x+1 = 63
x+x=2x , 2x+1=63
by transposition one will go to right hand side
so equation would be
2x=63-1
2x = 62
x=62\2
x=31
given that sum of consecutive no is 63
So, x+x+1 = 63
x+x=2x , 2x+1=63
by transposition one will go to right hand side
so equation would be
2x=63-1
2x = 62
x=62\2
x=31
RahulSingh1111:
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