The construction of a ∆ABC in which AB=5cm , angle A=60° , is not possible when sum of BC and AC is
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1.Draw AB of 5cm
2.With B as a centre construct 60°and extend the ray BX
3.On ray BX mark an arc of 9.8cm at Y
4.Draw perpendicular bisector of ray BY meeting on BX at C
5.Join AC
Therefore,ABC is the required triangle.
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