The conventional current I in a long straight wire flows in the upward direction as shown in the figure.
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The B field at the location of the charge +e is created by the wire next to it and given by B = μoI / 2πR. Based on RHR curl the direction of that B field is into the page at that location. Then the force on that charge is given by Fb = qvB, with q=e and B from before so Fb = ev(μoI / 2πR). Using the RHR flat for the + charge, the force comes out as down.
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