Question

The conversation of molecules X to Y follows second order kinetics.
If concentration of X is increased to three times how will it affect the rate of formation of Y​

Answer 1

For the reaction, x ---> y as it follows second order kinetics, the rate low equation will be

Rate=K[ X ] ^2 = ka^2

[ x ] = a mol

If concentration of X is increased three times , now

[x] = 3a mol ^-1

Rate =K (3a)^2

=9Ka^2

Thus , the rate reaction will become 9 times

Hence the rate of formation of Y will increase 9 times

Answer 2

since it follows second order kinematics,

X ------> Y

rate = k[Y]^2

let a be the concentration of x

therefore, initial rate =

ka^2

when concentration of x is increased by three times,

rate = (3a)^2

= 9a^2

thus rate increases by nine times.