Question

The coordinates of a and b are (-4,8) and (x,3) respectively. If ab=13, then the possible values of x are

Answer 1

a(-4,8)

b(x,3)

Length ab = 13

Solve x:

$\boxed {\boxed {\text {Length = } \sqrt{(Y_2-Y_1)^2 + (X_2- X_1)^2} }}$

$13 =\sqrt{(3-8)^2 + (x+4)^2}$

$13^2 =25 + (x+4)^2$

$(x+4)^2 = 169 - 25$

$(x+4)^2 = 144$

$x+4 = \pm \sqrt{144}$

$x+4 = \pm 12$

$x= \pm 12 - 4$

$x= -16 \text { or } x = 8$

Answer: The possible value of x is -16 or 8

Answer 2

Answer:

Step-by-step explanation: