Question

the coordinates of a point on Y-axis equidistant from (-5,-2)and(3,2)are=?

Answer 1

so u want the answer ,
here is the solution
from question we can se x = 0
and
using distance formula ,

(see diagram)
AC =
$\sqrt{ {( - 5 +0) }^{2} + {( - 2 + y)}^{2} }$
BC =
$\sqrt{ {(3 + 0)}^{2} + {(2 + y)}^{2} }$
as. AC = BC
$25 + 4 + {y}^{2} - 4y = \\ 9 + 4 + {y}^{2} + 4y$
$16 = 8y$
$y = 2$
so coordinates are
(0,2)