Question

the coordinates of the midpoint joining the points (sin square theta,sec square theta) and (cos square theta,- tan square theta) is ​

Answer 1

The coordinate of the midpoint of the given two points is (0.5,0.5)

-Given points

(x1,y1) = ( sin²θ , sec²θ ).......1

(x2,y2) = ( cos²θ , -tan²θ )........2

-According to midpoint formula,

midpoint (x,y) = ( (x1+x2)/2 , (y1+y2)/2 )......3

-By substituting 1 and 2 in 3

we get

midpoint (x,y) = ( (sin²θ + cos²θ)/2 , (sec²θ - tan²θ)/2 )

          => (x,y) = ( 1/2 , 1/2 )