The coordinates of the point of intersection of lines ax +by =9 and bc+ay=5 is (3,-1) .Find the value of a and b
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ax+by=9,bc+ay=5. soln.a into 3 + b into (-1) =9 ,b into 3+ a into (-1)=5. 3a-b=9,a-3b=-5 multiply a-3b=-5 by 3 we get,3a-9b=-15 now solve by subtracting both eqns we get a=4 and b=3
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