Question

The coordinates of the point
om x-axis which is equidistant
from points (-3,4) and (2,5) are​

Answer 1

Answer:

The point P(0,2)

Step-by-step explanation:

Let the point be P(0,y)

Given : A(-3,4)   B(2,5)

            AP = BP

(-3)2 + (4-y)2 = (2)2 + (5-y)2

9+16+y2-8y=4+25+y2-10y

9+16-8y=4+25-10y

2y = 29-25

y = 2

The point P(0,2)

Answer 2

answer will be

y= 2

hope this will help you