the coordinates of the point where the line 2(x-3)=y-8, meet the x-axis
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=> eqn of line : 2x - 6 = y - 8
for meeting the x-axis , coordinate of ' x ' will be 0
=> 2×0 - 6 = y - 8
=> -6 + 8 = y
=> y = 2
so the coordinates of the point will be P(0,2)
_______________
hope this helps!
=> eqn of line : 2x - 6 = y - 8
for meeting the x-axis , coordinate of ' x ' will be 0
=> 2×0 - 6 = y - 8
=> -6 + 8 = y
=> y = 2
so the coordinates of the point will be P(0,2)
_______________
hope this helps!
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