Question

the coordinates of vertices of triangle (-2,4) (3,-1) (1,a) and it's area is 10sq unit find the value of a ? Question from determinants.​

Answer 1

Answer:

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explained

Solution

The area of the triangle with vertices (k,0),(4,0) and (0,2) is given by the relation,

=21k40002111

⇒21[−2k+8]=±4

⇒−k+4=±4

Hence, k=0,8.