The correct order of electronegativity of underlined elements
a) C_2H4<C_2H2
b) O_F2<Na2O_
Attachments:
Answers
Answered by
10
Answer:
1st option is correct because c2h2 is sp hybridised so s% is 50% and we know that greater the percentage s character, greater will be the electronegativity.
hope it helps..
Similar questions