Science, asked by medhihirak3, 1 year ago


The correct order of increasing number of alpha particles passing undeflected through the
foils of Au, Ag, Cu and Al of 1000 atoms thickness each in a simulated alpha particles
scattering experiment of Rutherford would be
1. Au < Ag < Cu< Al
2. AI < Cu< Ag < Au
3. Au < Cu < Al < Ag
4. Ag < Cu< Al < Au

Answers

Answered by Anonymous
4

Answer:

1. Au < Ag < Cu< Al is the correct answer.

Explanation:

To find : The correct order of increasing number of alpha particles passing undeflected through the

foils of Au, Ag, Cu and Al of 1000 atoms thickness each in a simulated alpha particle scattering experiment of Rutherford.

In this experiment, Rutherford made a model where alpha rays were incident on

the thin sheet of gold foil. The observations were made on the basis of the scattering of alpha particles.

So the correct order of increasing number of alpha particles passing undeflected through the foils of Au, Ag, Cu and Al is

Au < Ag < Cu< Al.

The deflection of alpha particles increases with the increasing size of nucleus as observed in the above trend. This condition is for same thickness of coil.

Answered by ronakbhavsar495
4

Answer:

  • When we get the decreasing order for the nucleus of an atom, it comes down to Au > Ag > Cu > Al.
  • Therefore, if  we were to find out the correct answer in the increasing order for the alpha particles which passes through the Au foils then it would come down to Au < Ag < Cu < Al.

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