Question

The correct set of four quantum numbers for the valence electron in a hydrogen atom 1,0,0,+1/2
1,1,0,-1/2
1,1,0,+1/2
None of the above

Answer 1

Answer:

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Explanation:

E.C of Rubidium is (Z=37) = 1s22s22p63s23p64s23d104p65s1

 

The valence electron is in 5s orbital.

Its 4 quantum numbers are- n=5,l=0,m=0,s=+21

Therefore, the correct option is C

Answer 2

Answer:

1, 0,0,+1/2

Explanation:

$hydrogen \: \\ \\ electronic \: configuration = 1s ^{1} \\ n = 1 \\ l = 0 \\ m = 0 \\ s = + \frac{1}{2}$