The correct stability order of the following resonance
structures is
+ –
H₂C = N = N
(I)
+ –
H₂C – N = N
(II)
– +
H₂C – N = N
(III)
– +
H₂C – N = N
(IV)
(a) (I) > (II) > (IV) > (III) (b) (I) > (III) > (II) > (IV)
(c) (II) > (I) > (III) > (IV) (d) (III) > (I) > (IV) > (II)
Answers
Answered by
1
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Answered by
1
(III) > (I) > (IV) > (II) is the stability order.
Explanation:
- The stability of the resonance structure depends on the positioning of the charges on different atoms.
- The structure 2 says that the nitrogen is having negative charge along with 3 bonds which is not possible.
- So its least stable.
- While structure 3 shows that it has most stable structure of nitrogen with a positive charge and 4 bonds.
- The intermediate structure shows one is having positive on nitrogen and other having negative on nitrogen.
- So negative on nitrogen is more stable.
- Thus the stability trend is (III) > (I) > (IV) > (II).
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