Chemistry, asked by Anonymous, 6 months ago

The cost of 2 chairs and 3 tables is Rs.1300. The cost of 3 chairs and 2 tables is Rs.1200. The cost of each table is more than that of each chair by?​

Answers

Answered by Anonymous
2

The cost of 2 chairs and 3 tables is Rs.1300. The cost of 3 chairs and 2 tables is Rs.1200. The cost of each table is more than that of each chair by?

A top software development tool used by agile teams.

Let consider chair as x and table as y

According to the question

2x + 3y = ₹ 1300…..eq 1

3x +2y = ₹ 1200……eq 2

Multiply eq 1 by 3 and eq 2 by 2

6x + 9y = ₹3900

6x + 4y = ₹2400

Now subtract eq 2 from eq 1, we get

5y = ₹1500

Y = ₹300

Now put the value in eq 2

6x +4×300 =₹ 2400

6x +1200 =₹ 2400

6x = ₹ (2400–1200)

6x = ₹1200

X = ₹ 200

Chair price = x = ₹200

Table price = y = ₹300

Cost of each table is more than that of chair = ₹(300–200) = ₹100 Ans…

Answered by itZzAnshu
0

\large\underline{ \underline{ \sf \maltese{ \: Question⤵ }}}

➡ The cost of 2 chairs and 3 tables is Rs.1300. The cost of 3 chairs and 2 tables is Rs.1200. The cost of each table is more than that of each chair by ?

❇ Solution ⬇

Let consider chair as x and table as y

According to the question

➠ ️2x + 3y = ₹ 1300---[1]

➠ ️3x +2y = ₹ 1200----[2]

Multiply eq 1 by 3 and eq 2 by 2

➠ ️6x + 9y = ₹3900

➠ ️6x + 4y = ₹2400

Now subtract eq 2 from eq 1, we get

➥ 5y = ₹1500

➥ Y = ₹300

Now put the value in eq 2

➥ 6x + 4 × 300 = ₹ 2400

➥ 6x + 1200 = ₹ 2400

➥ 6x = ₹ (2400 - 1200)

➥ 6x = ₹1200

➥ X = ₹ 200

Chair price = x = ₹200

Table price = y = ₹300

  • Cost of each table is more than that of chair = ₹(300–200) = ₹100 .

Thank you.

Similar questions