Question

The cost of 2 chairs and 3 tables is Rs.1300. The cost of 3 chairs and 2 tables is Rs.1200. The cost of each table is more than that of each chair by-?​

Answer 1

Answer:

let cost a chair be RS x and cost of a table be RS y.

2x + 3y = RS 1300 [ equation-1]

3x + 2y = RS 1200 [ equation-2]

multiply equation 1 by 3 and equation 2 by 2

6x + 9y = RS 3900

6x + 4y = RS 2400

now, subtract equation 1 from equation 2

6x + 9y -( 6x + 4y) = RS 3900 - RS 2400

6x + 9y - 6x - 4y = RS 1500

5y = RS 1500

y = RS 1500/5

y = RS 300

now put value of y in equation 1

2x + 3y = RS 1300

2x + 3(300 RS) = RS 1300

2x + RS 900 = RS 1300

2x = RS 1300-Rs 900

2x = RS 400

x = RS 200

so, cost of table is RS 100 more than that of each chair

I hope my answer will help u

Answer 2

$\huge\bold{Question :-}$

The cost of 2 chairs and 3 tables is Rs.1300. The cost of 3 chairs and 2 tables is Rs.1200. The cost of each table is more than that of each chair by

$\huge\bold{Answer :-}$

Let cost a chair be RS x and cost of a table be RS y.

2x + 3y = RS 1300 [ equation-1]

3x + 2y = RS 1200 [ equation-2]

multiply equation 1 by 3 and equation 2 by 2

6x + 9y = RS 3900

6x + 4y = RS 2400

now, subtract equation 1 from equation 2

6x + 9y -( 6x + 4y) = RS 3900 - RS 2400

6x + 9y - 6x - 4y = RS 1500

5y = RS 1500

y = RS 1500/5

y = RS 300

now put value of y in equation 1

2x + 3y = RS 1300

2x + 3(300 RS) = RS 1300

2x + RS 900 = RS 1300

2x = RS 1300-Rs 900

2x = RS 400

x = RS 200

so, Cost of table is RS 100 more than that of each chair.

$\sf \red {Hope\:It\:Helps\:!!}$