Question

The cost of 2 kg of apples and l kg of grapes on a day was found to be Rs 160. After a month, the cost of 4 kg of apples and 2 kg of grapes is Rs 300. Represent the situation algebraically and geometrically.

Answer 1

situation algebraically and graphically will be as follows:

•Let the cost of 1 kg apple be x

•Let the cost of 1 kg grapes be y

•situation 1 . 2x+y=160

•situation 2. 4x+2y=300

•for GRAPHICAL solution please see attachment.

Answer 2

Answer:

The points are (50 , 60)  ,  (60 , 40) and  (50 , 50)  ,  (60 , 30) , The points are shown on graph

Step-by-step explanation:

Given as :

The cost of 2 kg of apples and 1 kg of grapes on a day  = Rs 160

The cost of 4 kg of apples and 2 kg of grapes on other day =  Rs 300.

Let The cost of apples per kg = Rs a

Let The cost of grapes per kg = Rs g

According to question

quantity of apple × cost of apple per kg + quantity of grapes × cost of grapes per kg = Total cost

So, 2 kg × Rs a per kg + 4 kg × Rs g per kg = Rs 160

i.e   2 a + g - 160 = 0           ......1

Similarly

    4 a + 2 g = 300             .

Or, 2 a + g = $\dfrac{300}{2}$

i.e  2 a + g - 150  = 0          ........2

Now, Plotting on graph

For eq 1

2 a + g - 160 = 0  

g = 160 - 2 a

for a = 50,

      g = 160 - 100 = 60

For a = 60

     g = 160 - 120 = 40

So, points are (a , g) = (50 , 60)  ,  (60 , 40)

Again

From eq 2

2 a + g - 150  = 0

g = 150 - 2 a

For a = 50

   g = 150 - 100 = 50

For a = 60

     g = 150 - 120 = 30

So, points are (a , g) = (50 , 50)  ,  (60 , 30)

Hence, The points are (50 , 60)  ,  (60 , 40) and  (50 , 50)  ,  (60 , 30) , The points are shown on graph Answer