The path of a train A is given by the equation 3x + 4y – 12 = 0 and the path of another train B is given by the equation 6x + 8y – 48 = 0. Represent this situation graphically.
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Answer:
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Given: The path of a train A is given by the equation 3x + 4y – 12 = 0 and the path of another train B is given by the equation 6x + 8y – 48 = 0.
Solution :
We have the following pair of linear equations :
3x + 4y – 12 = 0 ………..(1)
6x + 8y – 48 = 0 ………..(2)
To represent given situation graphically, we find at least two solutions for each equation.
For eq 1 :
3x + 4y – 12 = 0
On putting y = 0
3x + 4(0) = 12
3x = 12
x = 12/3
x = 4
Hence the coordinate is (4, 0)
On putting x = 0
3(0) + 4y = 12
4y = 12
y = 12/4
y = 3
Hence the coordinate is (0, 3)
3x + 4y – 12 = 0, passes through (4, 0) and (0,3)
For eq 2 :
6x + 8y – 48 = 0
On putting x = 0
6(0) + 8y = 48
8y = 48
y = 48/8
y = 6
Hence the coordinate is (0, 6)
6x + 8y – 48 = 0
On putting y = 0
6x + 8(0) = 48
6x = 48
x = 48/6
x = 8
Hence the coordinate is (8, 0)
6x + 8y – 48 = 0, passes through (0, 6) and (8,0)
Hope this answer will help you…
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