Math, asked by pratapnayak57, 1 day ago

The cost of 2 water bottles and 3 peelers is 1400. If the cost of a peeler is 50 more than that of a water bottle, find their costs. (Include how u solved it).
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Answers

Answered by outlook111021
5

Answer:

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Answered by khushikaul1506
3

Step-by-step explanation:

Let the cost of 1 water bottle be ₹x

Then the cost of 1 peeler = ₹(50 + x)

Cost of 2 water bottles = ₹2x

Cost of 3 peelers = 3(50 + x)

= ₹(150 + 3x)

Given that, the total cost of both the items is ₹1400

= (150 + 3x) + x = 1400

= 150 + 3x + x = 1400

= 150 + 4x = 1400

= 4x = 1400 - 150

= 4x = 1250

= x = 1250/4

= x = 312.5

Hence, cost of 1 water bottle is ₹312.5

So, the cost of 2 water bottles =

= 2 × 312.5

= ₹625

Also, the cost of 3 peelers =

= 150 + 3(312.5)

= ₹1087.5

...

Hope this helps :)

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