the cost of 21chairs and 15tables is 53700 the cost of seven chairs is 3500 less than the cost of 5tables .find the cost of chairs
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Answer:
21 chairs and 15 tables =53700
7 chairs and 5 tables = 17900
5 tables =x
7 chairs =x-3500
= x+x-3500=17900
= 2x=17900-3500
= 2x=14400
= x=14400/2
= x=7200
5 tables =7200
7 chairs =7200-3500=3700
Step-by-step explanation:
Answered by
2
Answer:
Step-by-step explanation:
Let x be the cost of one chair and y be the cost of one tables.
then,
21x+15y=53700/3
7x+5y=17900 ( in simple language we can write it) ....(i)
and 2nd situation,
7x+3500=5y
7x-5y=3500.....(.II)
on comparing equation (i) and (ii) we get
7x+5y=17900
7x-5y=3500
14x=14400
x=1028 (approx)
on putting the value of x on equ. (i)
7*1028+5y=17900
7196+5y=17900
5y=17900-7196
5y=10704
y=10704/5
y=2140(approx)
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