the cost of 28 geometry boxes is 658 rupees . how many boxes can be bought for rupees 1057.50?
SohamPatil:
Hey mate check out my answer it will surely help you!
Answers
Answered by
11
Hey mate
So here is how to solve it
658 rupees = 28 box
1 rupee = 28÷658 box
1057.5 rupees = (28÷658)×1057.5
Do the multiplication and you will get the answer.
Hope it helps (^o^)
So here is how to solve it
658 rupees = 28 box
1 rupee = 28÷658 box
1057.5 rupees = (28÷658)×1057.5
Do the multiplication and you will get the answer.
Hope it helps (^o^)
Answered by
11
Answer:
45
Step-by-step explanation:
Cost of 28 Geometry boxes = ₹ 658
Let the cost of one box be x
Hence according to the question,
28x = 658.
⇒ x = 658/28
∴ x = 23.5
Now, we have ₹ 1057.50
Let total number of boxes that can be bought with this money = y
When price of one box is ₹ 23.5
⇒ Boxes that can be bought with ₹ 1057.50
= 23.5y = 1057.50
⇒ y = 1057.50 ÷23.5
∴ y = 45
Hence 45 boxes can be bought with ₹ 1057.50
Hope this helps you!
If it does then please mark it as BRAINLIEST!
Regards,
Soham Patil.
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