Question

the cost of 28 geometry boxes is rupees 658 . how many boxes can be bought for rupees 1057.50 ?
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Answer 1

Answer:

45

Step-by-step explanation:

Cost of 28 Geometry boxes = ₹ 658

Let the cost of one box be x

Hence according to the question,

28x = 658.

⇒ x = 658/28

∴ x = 23.5

Now, we have ₹ 1057.50

Let total number of boxes that can be bought with this money = y

When price of one box is ₹ 23.5

⇒ Boxes that can be bought with ₹ 1057.50

= 23.5y = 1057.50

⇒ y = 1057.50 ÷23.5

∴ y = 45

Hence 45 boxes can be bought with ₹ 1057.50

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Answer 2

${\large{\bf{\clubs{\red{\underline{Given :}}}}}}$

The cost of 28 geometry boxes is rupees 658 .

￣￣￣￣￣￣￣￣￣￣￣￣

${\large{\bf{\clubs{\blue{\underline{To Find :}}}}}}$

how many boxes can be bought for rupees 1057.50 ?

￣￣￣￣￣￣￣￣￣￣￣￣

${\large{\bf{\clubs{\orange{\underline{Solution :}}}}}}$

${\sf{\purple{Cost \: of \: 28 \: geometry \: box = 658.00}}}$

Than,

${\sf{\purple{Cost \: of \: 1 \: geometry \: box = 658.00 \div 28}}}$

${\sf{\red{= 23.50 \: rupees }}}$

Next,

${\sf{\purple{Geometry \: box \: can \: be \: bought \: in \: 1057.50 ={ {\cancel \frac{1057.50}{23.50} }}}}}</u></p><p><u>[tex]{\sf{\purple{Geometry \: box \: can \: be \: bought \: in \: 1057.50 ={ {\cancel \frac{1057.50}{23.50} }}}}}$

${\tt{\red{\boxed{= 45 \: geometry \: boxes }}}}$

So,

${\mathfrak{\green{45 \: geometry \: boxes \: can \: be \: bought \: in \: Rs. 1057.50.}}}</u></p><p><u>[tex]{\mathfrak{\green{45 \: geometry \: boxes \: can \: be \: bought \: in \: Rs. 1057.50.}}}$

￣￣￣￣￣￣￣￣￣￣￣￣

${\large{\fcolorbox{red}{green}{\underline{\blue{XitzNobitaxX}}}}}$