Math, asked by shalomkhakha466, 1 month ago

the cost of 2kg of apples and 1kg of grapes on a day was found to be ru 160 after month, the cost of 4kg apples and 2kg of grapes is ru 300 . Represent the situation algebraically and geometrically

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Answered by firojabegum529

Answer:

Let us assume the cost of the one kg of apple be 'x' and the cost of one kg of grape be 'y'. We have given that the cost of 2 kg of apples and 1 kg grapes on a day was bound to be Rs. 160. So, we get 2x+y=160 ---(1).

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the cost of 2kg of apples and 1kg of grapes on a day was found to be ru 160 after month, the cost of 4kg apples and 2kg of grapes is ru 300 . Represent the situation algebraically and geometrically ​

Answers

the cost of 2kg of apples and 1kg of grapes on a day was found to be ru 160 after month, the cost of 4kg apples and 2kg of grapes is ru 300 . Represent the situation algebraically and geometrically