The cost of 4 notebooks, 3 bottles and 2 caps is Rs. 60. The cost of 2 notebooks, 4 bottles
and 6 caps is Rs. 90, whereas the cost of 6 notebooks, 2 bottles and 3 caps is Rs. 70. Find
the cost of each item using matrices (Method of Reduction).
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Answered by
2
Answer:
hello mate..
Step-by-step explanation:
Let book, notebook, pen be x, y, z respectively.
2x+6y+3z=40
3x+4y+2z=35
5x+7y+4z=61
⎣
⎢
⎢
⎡
2
3
5
6
4
7
3
2
4
⎦
⎥
⎥
⎤
⎣
⎢
⎢
⎡
x
y
z
⎦
⎥
⎥
⎤
=
⎣
⎢
⎢
⎡
40
35
61
⎦
⎥
⎥
⎤
Apply R
1
→R
1
−R
2
⎣
⎢
⎢
⎡
−1
3
5
2
4
7
1
2
4
⎦
⎥
⎥
⎤
⎣
⎢
⎢
⎡
x
y
z
⎦
⎥
⎥
⎤
=
⎣
⎢
⎢
⎡
5
35
61
⎦
⎥
⎥
⎤
Now R
1
→(−R
1
)
⎣
⎢
⎢
⎡
1
3
5
−2
4
7
−1
2
4
⎦
⎥
⎥
⎤
⎣
⎢
⎢
⎡
x
y
z
⎦
⎥
⎥
⎤
=
⎣
⎢
⎢
⎡
−5
35
61
⎦
⎥
⎥
⎤
R
2
→R
2
−3R
1
& R
3
→R
3
−5R
1
⎣
⎢
⎢
⎡
1
0
0
−2
10
17
−1
5
9
⎦
⎥
⎥
⎤
⎣
⎢
⎢
⎡
x
y
z
⎦
⎥
⎥
⎤
=
⎣
⎢
⎢
⎡
−5
50
86
⎦
⎥
⎥
⎤
R
2
→
10
1
R
2
,
⎣
⎢
⎢
⎢
⎡
1
0
0
−2
1
17
−1
−
2
1
9
⎦
⎥
⎥
⎥
⎤
⎣
⎢
⎢
⎡
x
y
z
⎦
⎥
⎥
⎤
=
⎣
⎢
⎢
⎡
−5
5
86
⎦
⎥
⎥
⎤
R
3
−17R
2
,
⎣
⎢
⎢
⎢
⎢
⎡
1
0
0
−2
1
0
−1
2
1
2
1
⎦
⎥
⎥
⎥
⎥
⎤
⎣
⎢
⎢
⎡
x
y
z
⎦
⎥
⎥
⎤
=
⎣
⎢
⎢
⎡
−5
5
1
⎦
⎥
⎥
⎤
Now x−2y−z=5, y+
2
z
=5,
2
z
=1
⇒z=2,y=4,x=5.
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