Question

the cost of 4chairs and 3tables is rs2100and the cost of 5chairs and 2tablesis1750 find the cost of one chair and one table separately

Answer 1

Let cost of 1 chair be  Rs. x 

     cost of be table be Rs. y 

According to the question, 

cost of 4 chairs and 3 tables is  Rs. 2100

So,  4x + 3y = 2100   ……...... (i) 

Also,

 cost of 5 chairs and 2 tables is Rs.1750 

So  5x + 2y = 1750 ……….. (ii) 

from equation (i) and (ii) 

 2 × (i) gives 8x + 6y = 4200  ……… (iii) 

 3 × (ii) gives 15x + 6y = 5250 ……….. (iV) 

{(iii) - (iV)} ,

15x + 6y – 8x – 6y = 5250 – 4200 

7x = 1050 

x=1050/7  

So, x = 150 

putting the value of x in equation (ii), we get  

⇒  5(150) + 2y = 1750 

⇒750 + 2y = 1750 

⇒2y= 1750 – 750 

⇒2y = 1000

⇒ y =1000/2

⇒ y =500

Hence,  cost of each chair,x = Rs. 150 

 cost of each table,y = Rs. 500