The cost of a chocolate is Rs. (x + y) and Amir bought (x + y) chocolates. Find the total
amount paid by him in terms of x and y. If x =10, y =5 find the amount paid by him.
Answers
Answered by
44
cost of chocolate =(x+y) Rs
no. of chocolates=(x+y)
total amount paid by him= cost of 1 chocolate×no. of chocolates
=(x+y)(x+y)=x^2+y^2+2xy
if x=10 and y=5
then amount will be 10^2+5^2+2(10)(5)
=100+25+100=250Rs
thanks
no. of chocolates=(x+y)
total amount paid by him= cost of 1 chocolate×no. of chocolates
=(x+y)(x+y)=x^2+y^2+2xy
if x=10 and y=5
then amount will be 10^2+5^2+2(10)(5)
=100+25+100=250Rs
thanks
Answered by
14
Answer:
The cost of (x+y) chocolates = rs. 289
Step-by-step explanation:
No. of chocolates =(x+y)
Cost of chocolates=(x+y)
Cost of (x+y) chocolates = (x+y)(x+y)
If x=10 and y=7
(10+7)(10+7)
10(10+7) +7(10+7)
100+70+70+49
= Rs. 289
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