Question

the cost of a turfing field at the raye of 45 rupees per 100m2 is 900 rupees .If double the base of triangle is 5 times the height .then,answer the above questions​

Answer 1

Answer:

YOUR QUESTIONS IS WRONG.....

YE QUESTION HAI OK

The cost of turfing a triangular field at the rate of Rs. 5 per sq.m is Rs. 1350 .If the sides of the field are in the ratio of 5:12:13. Find the sides of field .

2

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Answers

Given :-

Cost of turfing a triangular field @ Rupees 5 per m² is rupees 1350.

Therefore area of the triangular field = 1350/5

= 270m²

Now,

Ratio between the sides of the triangular field is given 5 : 12 : 13

Let the sides of the triangular field be 5x, 12x and 13x respectively.

➡ Semi-perimeter of the triangle = (5x + 12x + 13x)/2

= 15x

By using heron's formula, we get

√s(s - a)(s - b)(s - c) = area of the triangle where s is the semi-perimeter and a, b and c are it's sides respectively.

➡ √[15x(15x - 5x)(15x - 12x)(15x - 13x)] = 270m²

➡ √(15x × 10x × 3x × 2x) = 270m²

➡ √(900x⁴) = 270m²

➡ 30x² = 270m²

➡ x² = 270/30

➡ x² = 9

➡ x = √9

➡ x = 3

Hence, the sides of the triangular field are :-

5x = 5 × 3 = 15m

12x = 12 × 3 = 36m

13x = 13 × 3 = 39m

Answer 2

Answer:

Area of the triangular field

=  

45

100

​  

×900m  

2

 

=2000m  

2

 

Let base of the triangular field be x and height of the field be y

Given, 2x=5y

∴x=  

2

5y

​  

 

Now,

Area of the triangular field =  

2

1

​  

× base × height

⟹2000=  

2

1

​  

×x×y

⟹4000=  

2

5y

​  

×y

⟹y  

2

=1600

⟹y=40m