Math, asked by nandhinimanikan, 1 year ago

The cost of a washing machine depreciated by rs.720 during second year and by rs.648 during the third year.Calculate:i)the rate of depreciation per annum.ii)the original cost of the machine.iii)the value of the machine at the end of the third year.

Answers

Answered by VEDULAKRISHNACHAITAN
30

Answer:

i) 10 %

ii)Rs 7200

iii) Rs 5248.8

Step-by-step explanation:

Hi,

Let 'x' be the cost price of washing machine.

Let the annual rate of depreciation be r%

Depreciation during second year = r% of x = rx/100 = 720-----(1)

Value of washing machine after first year = Cost Price - Depreciation

Depreciation during third year = r% of (1 - r%)  x = rx(1 - r/100)/100 = 648-----(2)

Dividing (2)/(1), we get 1 - r/100 = 648/720 = 9/10

r/100 = 1/10

r = 10.

Hence the rate of depreciation per annum is 10 %

From (1), we have rx/100 = 720

10x/100 = 720

x/10 = 720

x = 7200 Rs.

Original Cost of the machine = Rs 7200

Value of the machine at the end of 1st year = x - 720

= 6480 Rs

Value of the machine at the end of 2nd year = 6480 - 648

= 5832 Rs

Value of the machine at the end of 3rd year = 5832 - 10%*5832

= 5832 * 9/10

= Rs 5248.8

Thus, value of machine at the end of 3 rd year = Rs 5248.8 .

Hope, it helps !

Answered by TooFree
21

Answer:

(i) 10%

(ii) Rs 7200

(iii) Rs 5248.80


Step-by-step explanation:

Find the rate:

Deprecation in the first year = Rs 720

Deprecation in the Second year = Rs 648

Rate of depreciation = (720 - 648)/720 x 100

Rate of depreciation = 10%


Find the original value of the washing machine:

Deprecation = 10%

Depreciation = Rs 720


10% = Rs720

1% = 720 ÷ 10 = Rs 72

100% = 72 x 100 = Rs 7200


Find the value at the end of third year:

Value = 7200(1 - 10/100)³

Value = Rs 5248.80


Answer (i) 10% (ii) Rs 7200 (iii) Rs 5248.80

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