Question

The cost of bananas is increased by Re.I per dozen, one can get 2 dozen
less for Rs 840. Find the original cost of one dozen of banana. give explanation ​

Answer 1

Answer:

Let the cost of banana per dozen be Rs. X.

Amount for which bananas are bought = Rs. 840

No. of dozens of bananas for Rs 840 =840/x

New cost of banana per dozen = Rs. (x + 1)

new no of dizen of bananas for Rs.840=840/x+1

According to given condition,

840/x-840 / x + 1 = 2

.: 840[1/x – 1/x+1] = 2

:: 840 [x+1- x / x(x+1)] = 2

:: 840 [1/(x²+ x)] = 2

:: 840 = 2(x²+ x)

:: 840 = 2(x² + x)

.: 2x2 + 2x – 840 = 0

Dividing by 2, we get

x² + x - 420 = 0 =

x² – 20x + 21x - 420 = 0

.: x (x – 20) + 21 (x – 20) = 0

.. x- 20 = 0 or x + 21 = 0

.. x = 20 or x = -21

:. The cost of bananas cannot be negative.

.. x = 20

The original cost of one dozen banana is

=Rs. 20

Answer 2

Step-by-step explanation:

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