Question

the cost of ploughing a rectangular field whose length is 15 m and breadth is 20 m is Rs 20 / m^2. if the length of rectangle is increased by 20 % and breadth by 25%.find the cost of ploughing field now

Answer 1

Solution:

Given:

• The length of rectangle=15m
• The breadth of rectangle=20m
• The cost of ploughing rate=Rs.20perm²

To Find:

• Total cost of ploughing field

According to the above information.

• If length is increased by 20% and breadth by 25% in the rectangle
• The new length of rectangle=15×120/100=18m
• The new breadth of rectangle=20×125/100=25m

Now, Find Area of rectangle,

$\sf{\longrightarrow Area=length*breadth}$

$\sf{\longrightarrow Area=18*25}$

$\sf{\longrightarrow Area=450\:m^2}$

Given,The cost of ploughing rate of field is Rs.20/m²

Hence,

$\sf{\longrightarrow Total\: cost\:of\: ploughing=450*20}$

$\sf{\longrightarrow Total\: cost\:of\: ploughing=9000}$

$\large\green{Answer:Rs.9000}$

Answer 2

Solution :

$\bf{\red{\underline{\bf{Given\::}}}}$

The cost of ploughing a rectangular field whose length is 15 m and breadth is 20 m is Rs.20/m². If the length of rectangle increased by 20% and breadth by 25%.

$\bf{\red{\underline{\bf{To\:find\::}}}}$

The cost of ploughing field now.

$\bf{\red{\underline{\bf{Explanation\::}}}}$

$\underbrace{\bf{1_{st}\:Case\::}}}}}$

• Length of rectangular field is 15 m.
• Length increased by 20% of field.

So, we need have to find new length of the rectangular field :

$\mapsto\sf{15\times (20\%+100\%)}\\\\\\\mapsto\sf{15\times \dfrac{20}{100} +100}\\\\\\\mapsto\sf{\cancel{15}\times \dfrac{\cancel{12}\cancel{0}}{\cancel{10}\cancel{0}} }\\\\\\\mapsto\sf{(3\times 6)m}\\\\\\\mapsto\sf{\pink{18\:m}}$

$\underbrace{\bf{2_{nd}\:Case\::}}}}}$

• Breadth of rectangular field is 20 m.
• Breadth increased by 20% of field.

So, we need have to find new breadth of the rectangular field :

$\mapsto\sf{20\times (25\%+100\%)}\\\\\\\mapsto\sf{20\times \dfrac{25}{100} +100}\\\\\\\mapsto\sf{\cancel{20}\times \dfrac{125}{\cancel{10}\cancel{0}} }\\\\\\\mapsto\sf{\cancel{\dfrac{125}{5} }}\\\\\\\mapsto\sf{\pink{25\:m}}$

A/q

We know that formula of the area of rectangle :

$\bf{\boxed{\bf{Area\:of\:rectangle=Length\times breadth\:\:\:\:(sq.unit)}}}}$

$\longrightarrow\sf{Area_{field}=New\:length\times New\:breadth}\\\\\longrightarrow\sf{Area_{field}=(18\times 25)m^{2} }\\\\\longrightarrow\sf{\pink{Area_{field}=450\:m^{2} }}$

$\underline{\underline{\sf{The\:cost\:of\:ploughing\:field\:now\::}}}}}}$

$\longrightarrow\sf{1m^{2} =Rs.20}\\\\\longrightarrow\sf{450m^{2} =Rs.(20\times 450)}\\\\\longrightarrow\sf{\green{Total\:cost\:=Rs.9000}}$