Economy, asked by ziniyakhan, 1 year ago

The cost of production 10800 rupees if two years so that 10 % of cost increasing find the compound interest ?

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Answers

Answered by HighRatedGabru144

CI = successive percentage change ( for 2 years)
=> 10 + 10 +(10×10)/100
=>20 + 100/100
=> 20+ 1 = 21%
again ,
100 % = 10800
1 % = 10800/100= 108
21 % = 108 × 21= 2268

Answered by adityanamdev0901

A=p(1+r/100)^n

A=10800(1+10/100or1/10)^2
A=10800×11/10×11/10
A=13068/-
CI=A-P=13068-10800 =2268/-
ANS=Rs2268

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