Math, asked by nituupadhyay77, 1 year ago

the cost of some books is rupees 60. cost of every book is the same.if the bookseller decreases the cost of any book by rs 1, one gets 5 book more for the same amount. what is the cost of each book and how many books are purchased?

Answers

Answered by TooFree
181

Answer:

Each book costs Rs 4 and 15 books are purchased.


Step-by-step explanation:

Define x:

Let the number of books be x


Find the cost of 1 book:

Total cost of the books = Rs 60

Cost of 1 book = 60 ÷ x  = 60/x


Find the new price if it decrease by Rs 1:

New Price = 60/x - 1


Solve x:

Cost of book decreased by Rs 1, number of purchase increased by 5

(60/x - 1)(x + 5) = 60

60 + 300/x - x - 5 = 60

300/x - x - 5 = 0

300 - x² - 5x = 0

x² + 5x - 300 = 0

(x - 15)(x + 20) = 0

x = 15 or x = -20 (rejected, since books purchased cannot be negative)


Find the number of books purchased:

Number of books = x = 15


Find the cost of a book:

Total cost = Rs 60

Number of books = 15

Cost of a book = 60 ÷ 15 = Rs 4



Answer: Each book costs Rs 4 and 15 books are purchased.


nituupadhyay77: thank you so much fun
pranavkassa: Thanks
varshu724: Thanks
varshu724: Thanks
balukahinath23: Thanks
savitafatangare1981: Thanks
Answered by shubhamjoshi033
107

Answer:

The cost of each book is Rs 4 and total number of books purchased were 15.

Step-by-step explanation:

Let the cost of each book = x

Let number of books = y

Hence xy = 60

=> y = 60/x

After the price reduction new price = x-1

Total number of books = y + 5

Hence we get,

(x-1)(y+5) = 60

=> xy +5x - y -5 = 60

=> 60 + 5x - 60/x -5 = 60

=> 5x - 60/x -5 = 0

=> x -12/x - 1 = 0

=> x² - x -12 = 0

=> x =  4 or -3

rejecting -3 we get x = 4

=> y = 60/4 = 15

Hence the cost of each book is Rs 4 and total number of books purchased were 15


nituupadhyay77: tysm
shubhamjoshi033: you are welcome
varshu724: thanks
Similar questions