Question

the cost of three balloon games exceeds the cost of four ring games by ₹4 ALSO, the total cost of 3 balloon shooting games and four ring games is ₹20 .

1) taking the cost of 1 ring game to be x and that of 1 balloon game as y , the pair of linear equation is ?
2) the points where the line represented by the equation 4x-3y = -4 intersects at the x-axis and y axis , respectively are given by:

Answer 1

Answer:

4x20=80 1x1=1 = 81 x4x3

Step-by-step explanation:

Ans

Answer 2

Given: The cost of three balloon games exceeds the cost of four ring games by ₹4 and the total cost of three balloon shooting games and four ring games is ₹20 .  

To find:

(i) The pair of linear equations.

(ii) The points where the line represented by the equation 4x - 3y = -4, intersects at the x-axis and y axis respectively.

Solution:

(i)

• According to the given statement, the cost of four ring games is Rs. 4 less than the cost of three balloon shooting games.

• If the cost of one ring game is equal to x and that of one balloon shooting game is y, then,

        $4x = 3y - 4$

        $4x - 3y = - 4$

• According to the given statement, the total cost of three balloon shooting games and four ring games is ₹20 .

       $4x + 3y = 20$

(ii)

• When we simultaneously equate these equations, we get,

        $x = 2$ and $y = 4$

Therefore, the pair of linear equations is 4x-3y=-4 and 4x+3y=20. The points at the x-axis and the y-axis are 2 and 4, respectively.