Math, asked by farukhis, 10 months ago

The cost of treatment per patient for a certain medical problem was modelled by one insurance company as a normal random variable with mean RS 775 and a standard deviation of RS 150. What is the probability that the treatment cost of a patient is less than RS 1,000, based on this model?

Answers

Answered by Alcaa
0

Answer:

0.93319 .

Step-by-step explanation:

We are given that the cost of treatment per patient for a certain medical problem was modeled by one insurance company as a normal random variable with mean RS 775 and a standard deviation of RS 150 i.e.;

 \mu = 775      and     \sigma = 150

Also, Z = \frac{X-\mu}{\sigma} ~ N(0,1)

Let X = treatment cost of a patient

P(X < 1000) = P( \frac{X-\mu}{\sigma} < \frac{1000-775}{150} ) = P(Z < 1.5) = 0.93319 {Directly from z table}

Therefore, probability that the treatment cost of a patient is less than RS 1,000, based on this model is 0.93319 .

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