the sum of two digit number and the number obtained by reversing its digits is 121 find the number if its unit place digit is greater than the 10th place digit by 7
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Let the unit digit is ‘x’ and the 10th digit is ‘y’
The number is 10 y +x
Reversed number is 10 x+y
Given 11 x+11 y =121`
x+y=11 [dividing by 11]…….1
Also x-y=3 ……2
solving 1 and 2 we get
x=7 and y=4
The number is 47 [check 47+74=121, 7–4=3]
HOPE THIS HELP YOU..
Let the unit digit is ‘x’ and the 10th digit is ‘y’
The number is 10 y +x
Reversed number is 10 x+y
Given 11 x+11 y =121`
x+y=11 [dividing by 11]…….1
Also x-y=3 ……2
solving 1 and 2 we get
x=7 and y=4
The number is 47 [check 47+74=121, 7–4=3]
HOPE THIS HELP YOU..
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