Question

The cost of two chairs and three tables is 1,300.
The cost of three chairs and two tables is 1,200.
The cost of each table is more than that of each chair by______​

Answer 1

Answer:

Let cost of one chair be a

Cost of one table be b

2a + 3b = 1300               ------ 1

3a + 2b = 1200               ------ 2

Multiplying equation 1    x 3, we get

6a + 9b = 3900                  ---- 3

Multiplying equation 2   x 2, we get

6a + 4b = 2400                  -----4

Subtracting Equation 4 from equation 3

      6a + 9b = 3900

(--)   6a + 4b = 2400

    =       5b  =  1500

therefore we get

b = 1500/5  =   300

2a + 3b = 1300

2a = 1300 - (3 x 300)

2a = 1300 - 900 =  400

a = 400/2  = 200

Cost of one table = RS 300

cost of one chair =  RS 200

Step-by-step explanation:

Answer 2

Answer:

100

Step-by-step explanation: