Question

The cost of vehicle is rupees 60000 if its value depreciated @ 20% per annum then the total depreciation after 3 years will be *​

Answer 1

Given :-

• Principal = Rs,60000
• Rate = 10%
• Time = 3years

To Find :-

• Total depreciation after 3 years ( Interest )

Solution :-

${:} \longrightarrow \sf{\sf{Interest\: = \:\dfrac{Principal \: \times \: Rate \: \times \: Time}{100} }}\\\\ {:} \longrightarrow \sf{\sf{Interest\: = \:\dfrac{60000 \: \times \: 20 \: \times \: 3}{100} }}\\\\ {:} \longrightarrow \sf{\sf{Interest\: = \:\dfrac{600 \cancel{00} \: \times \: 20 \: \times \: 3}{1 \cancel{00}} }}\\\\ {:} \longrightarrow \sf{\sf{Interest\: = \:600 \: \times \: 20 \: \times \: 3 }}\\\\ {:} \longrightarrow \sf{\sf{Interest\: = \:12000 \: \times \: 3 }}\\\\ {:} \longrightarrow \sf{\bf{Interest\: = \:Rs,36000 }}$

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So, Total Depreciation after 3 years will be Rs,36000

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Answer 2

Step-by-step explanation:

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$\huge{\underline{\mathrm{Question}}}$

The cost of vehicle is rupees 60000 if its value depreciated @ 20% per annum then the total depreciation after 3 years will be?

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$\huge{\underline{\mathrm{Given\: :}}}$

$\sf\green{ ∴Principal = Rs,60000}$

$\sf\blue{ ∴Rate = 10 percent}$

$\sf\green{ ∴Time = 3years}$

$\huge{\underline{\mathrm{To\:Find\: :}}}$

$\sf\orange{⇒Interest}$

$\huge{\underline{\mathrm{Solution\: :}}}$

$\sf\blue{:⟶Interest=\frac{ Principal×Rate×Time}{100} }$

$\sf\blue{:⟶Interest= \frac{60000×20×3}{100} }$

$\sf\blue{ :⟶Interest= \frac{60000 ×20×3 }{100} }$

$\sf\red{:⟶Interest=600×20×3 }$

$\sf\red{:⟶Interest=12000×3}$

$\sf\pink{:⟶Interest=Rs,36000 }$

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So, Total Depreciation after 3 years will be Rs,36000.

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