Question

The cost price of a machine is 250000 if the rate of depreciation is 10% per year find the depreciation in price of the machine after 2 years

Answer 1

Hey friend

Here is your answer

CP= 250000

Rate= 10%

Time= 2 years

250000(1-10/100)^2

250000(1-1/10)^2

250000(9/10)^2

250000(81/100)

= Rs.202500

The cost after 2 years is Rs.202500

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Answer 2

$\huge \underline \mathfrak {Solution:-}$

Cost of machine (P) = 250000 rupees

It will be depreciated for two years at 10% per year.

Time = 2 years

Rate of depreciation = 10 %

Amount

$= P {(1 - \frac{Rate}{100}) }^{Time} \\ \\ = 250000 {( 1-\frac{10}{100}) }^{2} \\ \\ = 250000 {( 1- 0.1) }^{2} \\ \\ = 250000 \times {0.9}^{2} \\ \\ =202500$

After 2 years it's cost will be 202500 rupees.

Depreciation = (250000-202500) rupees

Depreciation = 47500 rupees