The cost price of piece of diamond varies with square of its weight . A diamond of rs 12550 value is cut into 2 pieces whose weight are in ratio 2:5 Find the loss involved in cutting(weight 35kgs)
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Price of diamond = Rs.5184. As price is proportional to square of weight of diamond, weight of diamond = √5184 = 72.
This weight of 72 units is divided in the ratio 1 : 2 : 3.
Hence their weights are (1/6)x72, (2/6)x72, (3/6)x72v OR 12, 24, 36 units by weight.
Hence their price are 12², 24², 36² , i.e., 144, 576, 1296.
Hence total price of three pieces = 144+576+1296 = 2016.
Therefore loss involved in cutting = 5184 - 2016 =
This weight of 72 units is divided in the ratio 1 : 2 : 3.
Hence their weights are (1/6)x72, (2/6)x72, (3/6)x72v OR 12, 24, 36 units by weight.
Hence their price are 12², 24², 36² , i.e., 144, 576, 1296.
Hence total price of three pieces = 144+576+1296 = 2016.
Therefore loss involved in cutting = 5184 - 2016 =
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Answer: Question is a bit Ambiguous. Rs. 12550 and 35 kg do not satisfy the given condition i.e., equation (i)
Step-by-step explanation:
Cost Price of Diamond = (Weight)² -----(i)
35 Kg Diamond is cut into 2 parts in 2:5 ratio.
Sum of Ratio's = 7
Weight of First part = (2/7)*35=10kg
Weight of Second Part = (5/7)*35=25kg
Cost of First Part = 10²=Rs. 100
Cost of Second Part = 25² = Rs. 625
Total Cost of Both Parts = 100+625=Rs.725
Initial Price = Rs.12550
Note :
Rs. 12550 and 35 kg do not satisfy the given condition i.e., equation (i)
Final Price = Rs. 725
Loss = 12550-725 = Rs. 11825
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