Question

the count of bacteria in a culture was initially 525000. if it is increasing a rate of 7/2% per hour. find the count of bacteria at the end of 2 hours

Answer 1

No. of bacteria = 525000

$the \: percentage \: at \: which \: it \: changes \: per \: hour \: =$

$\frac{7}{2}\% \: per \: hour$

now ,

therefore,

no. of bacteria increasing per hour = 7/2% of 525000 = 525000/100×7/2 = 36,750 bacterias per hour ..

now ,

in 2hrs it will increase = 2×36,750 = 73,500 bacterias .

now ,

at the end of 2hrs the no. of bacteria = 73500+525000 => 5985000

hope it helps !!!

All the best !!

Answer 2

Answer:

5985000

Step-by-step explanation:

p(1-r/100) ki power4

=5985000