Question

the couple of force exhibits the​

Answer 1

Explanation:

Mass of the girl, m=50kg

Diameter of the heel, d=1cm=0.01m

Radius of the heel, r=2d=0.005m

Area of the heel =πr2

                            =π×(0.005)2

                            =7.85×10−5m2

Force exerted by the heel on the floor:

F=mg

    =50×9.8

    =490N

Pressure exerted by the heel on the floor:

P=AreaForce

    =490/(7.85×10−5)=6.24×106N/m2

Therefore, the pressure exerted by the heel on the horizontal floor is 6.24×106N/m2.

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